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The Double Transversality

Alexander S. Petty

Abstract

At a fixed base and lag, centering leaves a finite collision signal on the units modulo a power of the base. Its character expansion pairs exact collision coefficients with finite prime-character sums. Direct evaluation at bases three, five, and seven gives fourteen higher-lag tests. Of the thirteen defined magnitude correlations, twelve are negative. The sole positive value occurs at base three and lag two. At the deepest tested lag for each base, the correlation becomes more negative through five increasing prime cutoffs.

There is also an exact relation across bases. Centered collision signals from pairwise coprime bases become mutually orthogonal when lifted to their joint Chinese-remainder space. Their Fourier supports lie on disjoint coordinate axes, and the energy of every weighted combination is the sum of its separate base energies. The phrase double transversality joins the finite within-base observation to this proved cross-base orthogonality. Neither statement proves convergence below one or determines the location of zeros.

October 2024 (revised August 2026)
2020 Mathematics Subject Classification: 11A63, 11N05, 11M06

Introduction

Division at a fixed base and lag produces a finite collision table. After centering, that table has no principal component and no component inherited from the base alone. The surviving character coefficients record the exact finite geometry. Truncated prime-character sums record how primes meet the same characters up to a declared cutoff.

Two directions can then be separated. Within one base, the question is whether large collision coefficients are assigned to large or small prime-character sums as the lag increases. Across coprime bases, the question is whether the centered tables retain independent directions on a common finite space.

The second question has an exact answer. The Chinese remainder theorem places the lifted base signals on orthogonal coordinate axes. The first question is measured at finite cutoffs. The higher-lag data show a persistent negative assignment after two small base-three cases, but they do not supply an asymptotic theorem.

The distinction matters. Orthogonality on the complete finite state space does not imply cancellation along the primes. A finite correlation does not imply convergence. The exact identities and the numerical observations will be kept separate throughout.

The Finite Character Pairing

Fix a base b\geq 2 and a lag \ell\geq 1. Put m=b^{\ell+1}, \qquad U_m=(\mathbb Z/m\mathbb Z)^\times, and define the diagonal digit set G_{b,\ell}= \left\{0\leq n<m\ \middle| \left\lfloor\frac{n}{b^\ell}\right\rfloor=n\bmod b \right\}. The first and last base-b digits agree on this set, and |G_{b,\ell}|=b^\ell.

For a\in U_m, define the exact collision table T_{b,\ell}(a)= -1-\left\lfloor\frac ab\right\rfloor +\sum_{n\in G_{b,\ell}} \left( \left\lfloor\frac{(n+1)a}{m}\right\rfloor -\left\lfloor\frac{na}{m}\right\rfloor \right). No prime representative is needed to construct this table.

Reduction from U_m to U_b partitions the table into fibers A_u=\{a\in U_m\mid a\equiv u\pmod b\}, \qquad u\in U_b. Every fiber has b^\ell elements. Put \mu_{b,\ell}(u)= \frac1{b^\ell}\sum_{a\in A_u}T_{b,\ell}(a), \qquad f_{b,\ell}(a)=T_{b,\ell}(a)-\mu_{b,\ell}(a\bmod b).

Lemma 1 (The centered gate). For every a\in U_m, \begin{aligned} T_{b,\ell}(a)+T_{b,\ell}(m-a)&=-1, \\ f_{b,\ell}(m-a)&=-f_{b,\ell}(a). \end{aligned} Every reduction fiber has centered sum zero.

If \chi is a Dirichlet character modulo m, define \widehat f_{b,\ell}(\chi)= \frac1{\varphi(m)} \sum_{a\in U_m}f_{b,\ell}(a)\overline{\chi(a)}. Then \widehat f_{b,\ell}(\chi)=0 whenever \chi is even or factors through reduction from U_m to U_b.

Proof. Write D_n(a)= \left\lfloor\frac{(n+1)a}{m}\right\rfloor -\left\lfloor\frac{na}{m}\right\rfloor. For 1\leq n\leq m-2, complementary floors give D_n(a)+D_n(m-a)=1. The sums at n=0 and n=m-1 are zero and two. Both endpoints lie in G_{b,\ell}, so summing over that set gives \sum_{n\in G_{b,\ell}} \bigl(D_n(a)+D_n(m-a)\bigr)=b^\ell. Since a is a unit modulo b, \left\lfloor\frac ab\right\rfloor +\left\lfloor\frac{m-a}{b}\right\rfloor=b^\ell-1. Substitution into (1) proves (3).

Negation maps A_u bijectively onto A_{-u}. Averaging the raw reflection identity over one fiber gives \mu_{b,\ell}(u)+\mu_{b,\ell}(-u)=-1. Subtraction proves (4). The fiber sums vanish by the definition of the fiber means.

If \chi is even, reflection changes the sign of f_{b,\ell} and leaves \chi unchanged. Its coefficient is therefore zero. If \chi factors through reduction to U_b, it is constant on each A_u, and the zero fiber sums again force its coefficient to vanish. ◻

Call a character active when its coefficient in (5) is nonzero. Every active character is odd and does not descend to the base.

For a finite cutoff X>m and a real exponent \sigma>0, put \begin{aligned} P_X(\sigma,\chi)&= \sum_{m<p<X}\frac{\chi(p)}{p^\sigma}, \\ F_{b,\ell,X}(\sigma)&= \sum_{m<p<X}\frac{f_{b,\ell}(p\bmod m)}{p^\sigma}. \end{aligned}

Proposition 2 (Exact finite pairing). For every finite X>m and every \sigma>0, F_{b,\ell,X}(\sigma)= \sum_{\chi\ \mathrm{active}} \widehat f_{b,\ell}(\chi)P_X(\sigma,\chi).

Proof. Fourier inversion on U_m gives f_{b,\ell}(a)= \sum_{\chi\bmod m}\widehat f_{b,\ell}(\chi)\chi(a). Substitution into the finite prime sum proves (8). Lemma 1 removes every inactive term. ◻

The cutoff in (6) is part of the definition. No infinite value at \sigma=1/2 is assumed.

The Anti-Correlation at Higher Lags

The finite calculations were performed with nfield [1]. Every collision table was built directly from (1). The calculation checked reflection, every fiber sum, and the equality between the direct prime sum and the character decomposition. The largest decomposition error in the primary table was less than 2.4\mathbin{\cdot}10^{-14}. Runs with one and eight threads produced identical output.

The tested bases are three, five, and seven. The corresponding lag ranges are one through seven, one through four, and one through three. The primary cutoff is X=2{,}000{,}000 and \sigma=1/2. A coefficient was retained when its magnitude exceeded 10^{-10}. In every row, the only omitted odd characters were those proved inactive by Lemma 1.

For each retained character, the signed contribution is \operatorname{Re}\bigl( \widehat f_{b,\ell}(\chi)P_X(1/2,\chi) \bigr). The Pearson coefficient \rho compares the two retained lists \bigl|\widehat f_{b,\ell}(\chi)\bigr| \qquad\hbox{and}\qquad \bigl|P_X(1/2,\chi)\bigr|. It is reported only when both lists have nonzero variance. Conjugate characters are counted separately because they are separate terms in the full Fourier sum. Keeping one representative from each conjugate pair gives the same Pearson coefficient.

The finite computed ledger at X=2{,}000{,}000. Prime counts use m<p<X and therefore vary with the modulus. Proved inactive characters are not counted as positive contributions.
b \ell m primes retained/inactive +/- F_{b,\ell,X} \rho
3 1 9 148{,}929 2/1 2/0 +0.619 undefined
3 2 27 148{,}924 8/1 4/4 +1.183 +0.416
3 3 81 148{,}911 26/1 14/12 +0.617 -0.420
3 4 243 148{,}880 80/1 34/46 +4.825 -0.275
3 5 729 148{,}804 242/1 142/100 +12.771 -0.327
3 6 2{,}187 148{,}606 728/1 358/370 +29.145 -0.327
3 7 6{,}561 148{,}086 2{,}186/1 1{,}162/1{,}024 +10.358 -0.202
5 1 25 148{,}924 8/2 6/2 +1.035 -0.451
5 2 125 148{,}903 48/2 32/16 +4.009 -0.177
5 3 625 148{,}819 248/2 132/116 +2.483 -0.278
5 4 3{,}125 148{,}488 1{,}248/2 634/614 +15.257 -0.190
7 1 49 148{,}918 18/3 10/8 +1.812 -0.276
7 2 343 148{,}865 144/3 86/58 +7.564 -0.216
7 3 2{,}401 148{,}576 1{,}026/3 506/520 +4.584 -0.157

There are thirteen defined correlations. Twelve are negative. The one positive value occurs at base three and lag two. The lag-one base-three row has two conjugate active characters with equal coefficient magnitudes, so its Pearson coefficient is undefined rather than zero.

The three deepest tested rows were also followed through five increasing cutoffs. In each row the correlation becomes more negative throughout the declared range.

Pearson correlations at the deepest tested lag for each base.
b \ell 250{,}000 500{,}000 1{,}000{,}000 2{,}000{,}000 5{,}000{,}000
3 7 -0.052 -0.088 -0.141 -0.202 -0.247
5 4 -0.078 -0.102 -0.145 -0.190 -0.233
7 3 -0.047 -0.099 -0.130 -0.157 -0.214

Every primary-cutoff net in Table 1 is positive. That sign is not stable under a change of cutoff. At base three and lag seven, the finite net changes sign twice across the five cutoffs. A positive value at one cutoff therefore carries no conclusion about convergence.

Coprime Bases

The cross-base direction is exact. Let \mathcal B be a finite set of pairwise coprime bases. Choose a lag \ell_b\geq1 for each b\in\mathcal B and put m_b=b^{\ell_b+1}, \qquad M=\prod_{b\in\mathcal B}m_b. The Chinese remainder theorem identifies U_M\cong\prod_{b\in\mathcal B}U_{m_b}. Lift the centered signal from base b to U_M by \mathcal F_b(a)=f_{b,\ell_b}(a\bmod m_b). Use normalized counting inner products on every unit group, so \langle h,k\rangle_{U_q}= \frac1{\varphi(q)}\sum_{a\in U_q}h(a)\overline{k(a)}.

Theorem 3 (Coprime-base orthogonality). For distinct b,c\in\mathcal B, \langle\mathcal F_b,\mathcal F_c\rangle_{U_M}=0. Every lift has mean zero and \|\mathcal F_b\|_{U_M}=\|f_{b,\ell_b}\|_{U_{m_b}}. Consequently, for arbitrary complex weights w_b, \left\|\sum_{b\in\mathcal B}w_b\mathcal F_b\right\|_{U_M}^2 = \sum_{b\in\mathcal B}|w_b|^2 \|f_{b,\ell_b}\|_{U_{m_b}}^2.

Under the Chinese-remainder factorization of characters, the Fourier support of \mathcal F_b lies on the b coordinate axis. It is trivial in every other base coordinate. The nonzero Fourier supports of distinct lifted signals are disjoint.

For the weighted signal \mathcal F=\sum_b w_b\mathcal F_b, averaging over every coordinate except the b coordinate recovers w_bf_{b,\ell_b} exactly.

Proof. The mean of every centered table is zero. Under the product identification, the inner product of two distinct lifts factors as \left( \frac1{\varphi(m_b)}\sum_{a_b\in U_{m_b}}f_{b,\ell_b}(a_b) \right) \left( \frac1{\varphi(m_c)}\sum_{a_c\in U_{m_c}} \overline{f_{c,\ell_c}(a_c)} \right). Both factors vanish. Product counting also proves (10). Equation (9) follows, and expansion of the squared norm gives (11).

Every character of U_M factors uniquely as \chi=\prod_{c\in\mathcal B}\chi_c. The coefficient of \mathcal F_b at \chi is \widehat f_{b,\ell_b}(\chi_b) \prod_{c\ne b} \left( \frac1{\varphi(m_c)}\sum_{a_c\in U_{m_c}} \overline{\chi_c(a_c)} \right). The product vanishes unless every \chi_c with c\ne b is principal. The coefficient on the all-principal character also vanishes because f_{b,\ell_b} has mean zero. The remaining support lies only on the b coordinate axis. Distinct axes meet only at the absent principal character.

Finally, average \mathcal F over every coordinate other than b. The b term is constant under that average. Every other term has a zero mean in its own coordinate and disappears. The result is w_bf_{b,\ell_b}. ◻

Uniform counting on U_M makes its Chinese-remainder coordinates independent and uniform. The random variables \mathcal F_b are therefore independent, not only orthogonal. Conditional averaging shows that their weighted aggregate preserves every component having nonzero weight.

Pairwise coprimality gives the cleanest sufficient condition. There is an exact formula when two moduli share a factor.

Proposition 4 (The common quotient). Let m and n be positive integers, put L=\operatorname{lcm}(m,n), \qquad d=\gcd(m,n), and let f and g be functions on U_m and U_n. For u\in U_d, write E_{m\to d}f(u) and E_{n\to d}g(u) for the averages over the corresponding reduction fibers. Let \pi_m and \pi_n be reduction from U_L to U_m and U_n. Then \langle f\circ\pi_m,g\circ\pi_n\rangle_{U_L} = \langle E_{m\to d}f,E_{n\to d}g\rangle_{U_d}. Thus the only possible cross term passes through the common quotient U_d.

Proof. The generalized Chinese remainder theorem identifies U_L with the fiber product U_m\mathbin{\times_{U_d}}U_n. Here U_1 denotes the one-element group. Reduction from U_m and U_n to U_d is surjective, and every fiber of either group homomorphism has the same size. The common residue is therefore uniform on U_d. Conditioned on that residue, the two remaining coordinates are uniform and independent within their reduction fibers. The conditional inner product is E_{m\to d}f(u)\overline{E_{n\to d}g(u)}. Averaging over u proves (12). ◻

Global centering removes the principal common mode. It does not remove a nonconstant mode on U_d. Coprime moduli have a trivial common quotient, so their global zero means are sufficient for orthogonality. More generally, orthogonality follows whenever either conditional average in (12) vanishes identically.

For the ten prime bases 3,5,7,11,13,17,19,23,29,31, the theorem applies at lag one or at any independently chosen lags. The weight w_b=1/b^2 gives one possible combined readout, but the orthogonality does not depend on that choice. It holds for every set of weights.

An exact nfield audit built all ten lag-one tables and checked their 45 pairwise inner products in factored Chinese-remainder coordinates. Every cross term was exactly zero. The weighted Pythagorean identity for w_b=1/b^2 also held exactly. These checks support the implementation in nfield [1]. The proof of Theorem 3 does not depend on them.

The theorem concerns uniform counting on the complete joint unit group. Primes trace one arithmetic sequence through that product space. Their coordinates are not independent samples, so (9) does not assert cancellation of a prime sum.

The Double Transversality

The word double refers to two different directions.

Within a base, the exact character pairing joins the collision spectrum to finite prime-character sums. Twelve of the thirteen defined higher-lag correlations are negative at the primary cutoff. The deepest tested row in each base becomes more negatively correlated across the five declared cutoffs. This is finite evidence about the coefficient-to-character assignment.

Across pairwise coprime bases, the centered collision signals are exactly orthogonal. Their character supports occupy disjoint coordinate axes, and their energies add without cross terms. This is a theorem about the finite collision geometry.

The two statements do not prove one another. The computed within-base pattern uses primes and a cutoff. The proved cross-base pattern uses the complete finite state space and no primes. Their common content is that direction matters. Within a base, the coefficient assignment matters. Across bases, the Chinese-remainder coordinate matters.

Exact Orthogonality and Finite Data

The floor formula, reflection law, centered gate, finite character pairing, and coprime-base orthogonality are exact. None depends on a searched prime representative or a numerical fit.

The higher-lag correlations and signed nets are finite calculations. They use declared moduli, prime intervals, cutoffs, and retention thresholds. nfield checked every residue class in the fourteen collision tables and reproduced the complete ledger [1]. These calculations do not establish a limiting correlation.

Tail windows across bases depend on their starting point. Removing the initial prime segment can change the signs of the individual base contributions. At \sigma=1/2, nfield [1] evaluated the ten natural sums from b^2<p<X at cutoffs from 250{,}000 through 5{,}000{,}000. All fifty values were positive. Mixed signs appeared only after the initial segment through 997 was removed. This is finite evidence, not a positivity theorem. It shows why the exact orthogonality theorem must replace, rather than justify, a claim of prime-sum cancellation across bases.

The remaining problem is cutoff-uniform control of the higher-lag assignment and its effect on the surviving prime-character sum. Until such control is proved, there is no conclusion about convergence below one and no conclusion about zero locations.

References

[1]A. S. Petty, nfield, software repository. https://github.com/alexspetty/nfield