The Collision Transform and the Critical Strip

The Collision Transform and the Critical Strip
The centered sum enters the critical strip from the right. How far it penetrates depends on the zeros. Under GRH, it reaches the center.

The centered sum converges at $s = 1$. What about below?

The strip

The critical strip is the region $0 < \text{Re}(s) < 1$ where the zeros of $L$-functions live. The Riemann Hypothesis says they all sit at $\text{Re}(s) = 1/2$. The Generalized Riemann Hypothesis says the same for all Dirichlet $L$-functions.

The centered collision sum $F^\circ(s)$ converges at $s = 1$. Pushing it below $s = 1$ means entering the strip. The sum involves $P(s, \chi) = \sum_p \chi(p)/p^s$, which has singularities at the zeros of $L(s, \chi)$.

Conditional penetration

If every odd $L$-function modulo $b^2$ has no zeros for $\text{Re}(s) > \sigma_0$, then $F^\circ(s)$ converges for real $s > \sigma_0$.

Under GRH ($\sigma_0 = 1/2$): $F^\circ(s)$ converges all the way to $s = 1/2$. The collision invariant reaches the center of the strip.

Without GRH: the penetration depth is limited by the zero-free region. The classical zero-free region gives convergence only slightly below $s = 1$. The collision transform can see into the strip, but not deeply, without help from the zeros.

What this means

The collision invariant at $s = 1$ is unconditional. It converges because the centering removes the Mertens term.

The collision invariant below $s = 1$ is conditional. Its depth depends on where the $L$-function zeros are. If the zeros are well-behaved (on the critical line), the invariant sees deep. If not, it stops early.

The collision transform is a probe. The strip is the territory. The zeros are the obstacles.

Try it yourself

./nfield 7               # collision deviation data
./nfield 97              # feeds into the sum

Code: github.com/alexspetty/nfield


Alexander S. Petty
June 2025
.:.